A Train After Travelling 150 Km Meets With An Accident . Had the accident occurred 360 km further, it would have reached the destination 4 hours late. A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late.
SealdahAjmer express train derails near Kanpur Photos from www.ibtimes.co.in
(a) 960 km (b) 870 km (c) 840 km (d) 1100 km A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives at its destination 8 hours late. After this the train moves at 75% speed of its original speed and reaches to destination 4 hours late.
SealdahAjmer express train derails near Kanpur Photos
If the accident would occur at 150 km ahead in the same line then the train reaches only 3.5 hours late. If the accident would occur at 150 km ahead in the same line then the train reaches only 3.5 hours late. A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives at its destination 8 hours late. A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late.
Source: venturebeat.com
A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives at its destination 8 hours late. A train after travelling 50 km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late. A train after traveling 150 km.
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Let s = the normal speed of the train then If the accident would occur at 150 km ahead in the same line then the train reaches only 3.5 hours late. A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives at its destination 8 hours late. A) 36.
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I.e., after travelling $100$ km, $\dfrac{1}{4}$ of the original time to cover remaining distance is $45$ minutes. After travelling for 3 0 minutes a train meets with an accident, due to which it has to stop for 4 5 minutes. The length of journey is Had the accident occurred 360 km further, it would have reached the destination 4 hours.
Source: www.petrofilm.com
So the speed of the train after the accident is $ \dfrac{3}{4}x $ km/hr. Let s = the normal speed of the train then Had the accident occurred 360 km further, it would have reached the destination 4 hours late. A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and.
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Due to the accident its speed is also reduced to 3 2 of its former value and the train reaches its destination 1 hour 3 0 minutes late. If the accident would occur at 150 km ahead in the same line then the train reaches only 3.5 hours late. A train after traveling 150 km meets with an accident and.
Source: caymaneco.org
A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Total distance which needs to be covered = (300+150)m = 450m. Let y be the balance distance.
Source: caymaneco.org
A) 36 kmph b) 48 kmph c) 54 kmph d) 58 kmph Had the accident occurred 24 km further, it would have reached the destination only 25. A train meets with an accident and travels at 4/7th of its regular speed hereafter and hence it reaches its destination 36 minutes late. Thus, extra time = 2 hour. (a) 960 km.
Source: www.petrofilm.com
After this the train moves at 75% speed of its original speed and reaches to destination 4 hours late. Had the accident occurred 24 km further, it would have reached the destination only 25. A train after travelling 150 km meets with an accident and proceeds at `3/5`of its former speed and arrives at its destination 8 hours late. Had.
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A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late. (or original time is $45×4=180$ minutes $=3$ hour). #timeanddistancebyprabhakarsir #careeradhyapana train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives. Had the accident.
Source: suomiweed.com
What is the total distance travelled by the train ? So the speed of the train after the accident is $ \dfrac{3}{4}x $ km/hr. What is the total distance travelled by the train? Had the accident occurred 30 kms further, the train would have been late by only 21 minutes. After travelling 3 hours a train meets with an accident.
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Had the accident occurred 360 km further, it would have reached the destination 4 hours. What is the total distance traveled by the train?: Let us assume the distance the train has to cover after the accident as $ y $ km and the speed of the train before the accident is $ x $ km/hr. I.e., after travelling $100$.
Source: suomiweed.com
Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Now you can use d = s * t = 30 * 60/60 = 30 km. Let s = the normal speed of the train then A train after traveling 150 km meets with an accident and then proceeds with 3/5 of its former.
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Had the accident occurred 6 0 km later, the train would have reached 3 0 minutes earlier. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Now you can use d = s * t = 30 * 60/60 = 30 km. Had the accident occurred 360 km further, it would have reached.
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What is the total distance traveled by the train?: A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives at its destination 8 hours late. #timeanddistancebyprabhakarsir #careeradhyapana train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives. Had the.
Source: railcolornews.com
A train after travelling 50kms meets with an accident and then proceeds at 3/4th of its former speed and arrives at its destination 35 minutes late. Had the accident occurred 24 km further, it would have reached the destination only 25. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Had the accident.
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What is the total distance travelled by the train ? The delay in arrival is the time difference between the time the train takes to cover the rest distance $ y $ after the accident and time it would have taken without the. What is the total distance traveled by the train?: I.e., after travelling $100$ km, $\dfrac{1}{4}$ of the.
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A train after travelling 50 km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late. A train after travelling 150 km meets with an accident and proceeds at `3/5`of its former speed and arrives at its destination 8 hours late. A train after travelling 50kms meets with an.
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A train meets with an accident and travels at 4/7th of its regular speed hereafter and hence it reaches its destination 36 minutes late. After travelling 3 hours a train meets with an accident due to this it stops for an hour. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Had the.
Source: www.firstpost.com
After travelling for 3 0 minutes a train meets with an accident, due to which it has to stop for 4 5 minutes. A train after traveling 150 km meets with an accident and then proceeds with 3/5 of its former speed and arrives its destination 8 hours late. Had the accident occurred 360 km further, it would have reached.
Source: venturebeat.com
Let y be the balance distance to be covered and x be the former speed. (or original time is $45×4=180$ minutes $=3$ hour). It means it covers 300 km distance in 5 hours. A train meets with an accident and travels at 4/7th of its regular speed hereafter and hence it reaches its destination 36 minutes late. What is the.
